logx+2(2x^2+x)=1

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Solution for logx+2(2x^2+x)=1 equation:


Simplifying
logx + 2(2x2 + x) = 1

Reorder the terms:
glox + 2(x + 2x2) = 1
glox + (x * 2 + 2x2 * 2) = 1
glox + (2x + 4x2) = 1

Solving
glox + 2x + 4x2 = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-2x' to each side of the equation.
glox + 2x + -2x + 4x2 = 1 + -2x

Combine like terms: 2x + -2x = 0
glox + 0 + 4x2 = 1 + -2x
glox + 4x2 = 1 + -2x

Add '-4x2' to each side of the equation.
glox + 4x2 + -4x2 = 1 + -2x + -4x2

Combine like terms: 4x2 + -4x2 = 0
glox + 0 = 1 + -2x + -4x2
glox = 1 + -2x + -4x2

Divide each side by 'lox'.
g = l-1o-1x-1 + -2l-1o-1 + -4l-1o-1x

Simplifying
g = l-1o-1x-1 + -2l-1o-1 + -4l-1o-1x

Reorder the terms:
g = -2l-1o-1 + l-1o-1x-1 + -4l-1o-1x

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